AI SQL Query Generator
Server-poweredDescribe your data query in plain English and get SQL instantly
Describe your query in plain English. Be specific about filters, sorting, and grouping. Press Ctrl+Enter to generate.
Try an example
How It Works
Describe Your Query
Write what data you need in plain English. No SQL knowledge required. You can optionally include your table schema for more accurate results.
Choose Your Dialect
Select the SQL dialect that matches your database. The generator will use dialect-specific syntax, functions, and best practices.
Get Your SQL Query
Receive a properly formatted SQL query along with an explanation of what it does. Copy it and use it directly in your database client.
SQL Dialects Supported
Standard SQL
ANSI SQL compatible with most databases
MySQL
World's most popular open-source database
PostgreSQL
Advanced open-source relational database
SQLite
Lightweight embedded database engine
SQL Server
Microsoft's enterprise database system
Oracle
Enterprise-grade relational database
Example Queries
Prompt: Show me all customers who haven't placed an order in the last 6 months
SELECT c.id, c.name, c.email, MAX(o.created_at) AS last_order
FROM customers c
LEFT JOIN orders o ON c.id = o.customer_id
GROUP BY c.id, c.name, c.email
HAVING MAX(o.created_at) < NOW() - INTERVAL '6 months'
OR MAX(o.created_at) IS NULL
ORDER BY last_order ASC;Prompt: Get monthly revenue totals for this year, compared to last year
SELECT
EXTRACT(MONTH FROM created_at) AS month,
SUM(CASE WHEN EXTRACT(YEAR FROM created_at) = EXTRACT(YEAR FROM NOW())
THEN total ELSE 0 END) AS current_year,
SUM(CASE WHEN EXTRACT(YEAR FROM created_at) = EXTRACT(YEAR FROM NOW()) - 1
THEN total ELSE 0 END) AS previous_year
FROM orders
WHERE created_at >= DATE_TRUNC('year', NOW()) - INTERVAL '1 year'
GROUP BY month
ORDER BY month;Prompt: Find duplicate email addresses across all users
SELECT email, COUNT(*) AS occurrences
FROM users
GROUP BY email
HAVING COUNT(*) > 1
ORDER BY occurrences DESC;